In figure PQRS is a parallelogram QU and ST are perpendiculars on the diagonal PR prove that :
1. ∆STR is congruent to ∆QUP 2. ST = QU
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In ΔPXS and ΔRYQ
PS = QR (opp sides of paralleogram)
angle PXS = angle RYQ = 90 degrees
angle PSX = angle YQR (alternate interior angles)
By AAS two triangles are congruent.
By CPCT PX = RY
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Given:
PQRS is a parallelogram
QU and ST are perpendiculars on the diagonal PR
To Find:
1. ∆STR ≅ ∆QUP
2. ST = QU
Solution:
1. In order to prove the congruency, we see that
∠STR =∠QUP = 90° (Given)
SR = PQ (Opp.sides of parallelogram are equal )
∠SRT = ∠QPU (alternate interior angle)
∆STR ≅ ∆QUP (By AAS)
2. By corresponding parts of congruent triangles, we get
ST = QU
Hence, ∆STR ≅ ∆QUP and ST = QU.
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