The perimeter of a semicircular protractor is 108cm.Find the diameter of the protractor.
Plz ans it fast....
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The perimeter of the semicircular protractor is half the perimeter of circular protractor i.e pi R plus the diameter i.e 2R.
So we know,
Perimeter = 108 cm
Pi R + 2R = 108
R( Pi +2)= 108
R( 22÷7 + 2) = 108
R× 36÷7 = 108
R= (108×7)÷7
R=21 cm
21cm is Answer
So we know,
Perimeter = 108 cm
Pi R + 2R = 108
R( Pi +2)= 108
R( 22÷7 + 2) = 108
R× 36÷7 = 108
R= (108×7)÷7
R=21 cm
21cm is Answer
Bjjat:
you did one step wrong
what ❓
which step
step no. 6
see you rote (108×7)÷7
so instead of that (108×7)÷36 will be come
hnmm..
☺️
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