Question

In figure, PQRS is a square. The diagonals RP and SQ intersect each other at K.T is a point on PQ such that PQ=PR , then ∠TKQ

Answer 1

To find ∠PQO and ∠PSQ.

PQRS is a rectangle, and O is the intersection point of diagonals PR and SQ.

PR=SQ [Diagonals of rectangle are equal]

PO=Qo [Diagonals of rectangle bisect each other]

∴∠PQO=∠OPQ→(1) [Angles opposite to equal sides]

In △POQ ,

∠PQO+∠POQ+∠OPQ=180

∘

2∠PQO+110

∘

=180

∘

[From (1)]

∠PQO=

2

180

∘

−110

∘

=35

∘

Now, in △PQS

∠PQS+∠QPS+∠PSQ=180

∘

35 + 90 + <PSQ = 180⁰

∠

∠PSQ=180⁰

−125⁰

=55⁰