In figure, sides QP and RQ of ∆PQR are produced to points S and T, respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.
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Given :-
A Triangle PQR , sides QP and RQ are produced to"S" and " T" respectively
Angle SPR = 135
Angle PQT = 110
Required:-
Angle PRQ
Solution:-
We have
Angle 1 + Angle SPR = 180 ( LINEAR PAIR)
Angle 1 + 135 = 180
Angle 1 = 180 - 135
Angle 1 = 45
BY EXTERIOR ANGLE THEROM,
Angle PQT = Angle 1 + Angle 2
= 110 = 45 + Angle 2
= 110 - 45 = Angle 2
= 65 = Angle 2
So Angle PRQ = 65
Note :-
Figure in attachment
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