Question

in figure the line segment xy is parralel to side ac of ∆abc and it divides the triangle in to two parts of equal areas.find the ratio ax/ab​

Answer 1

Step-by-step explanation:

• 2 Area ( xy) = Area ( ABC)
• in ∆ ABC and ∆ XBY
• angle ABC = angle XBY ( Common)
• angle ACB = angle XYB ( Since XY parallel AC , angle are equal)
• ∆ ABC ~∆ XBY ( By AA criteria)
• Area( AB/XB) ^2= area (∆ABC) /
• area ( ∆ BXY) =2
• ( AB ) ^2 = 2 (XB) ^2 AB = √2×B
• AX = AB - XB = AB - AB /√2 = (√2-1 / √2) AB
• AX / AB = √2-1 /√2
• thank dear friend
• I hope you help