Question

In figure the shape of a solid copper piece made of two pieces with dimensions is shown. The face ABCDEFA is the uniform cross section. Assume that the angles A, B, C, D, E and F are right angles, calculate the volume of the piece.

Answer 1

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Answer 2

AnswEr:

$\underline\mathfrak{For\:the\:horizontal\:piece,\:we\:have}$

• Length = 8 cm
• Breadth = 22 cm
• Height = 3 cm

$\therefore$ $\sf{Volume\:of\:the\:horizontal\:piece}$

$\sf = (8 \times 22 \times 3) {cm}^{3} \\ \\ = \sf \: 528 \: {cm}^{3}$

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$\sf{For\:the\:vertical\:piece,\:we\:have,}$

• Length = 22 cm
• Breadth = 2 cm
• Height = (5+3) cm = 8 cm

$\therefore$ $\sf{Volume\:of\:the\:vertical\:piece:}$

$\sf = (22 \times 2 \times 8) {cm}^{3} \\ \\ \sf = 352 \: {cm}^{3}$

Hence, $\sf{Volume\:of\:the\:whole\:piece:}$

$\sf = (528 + 352) \: {cm}^{3} \\ \\ = \sf \: 880 \: {cm}^{3}$

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