Math, asked by abcde74, 1 year ago

In figure the sides BC of triangle ABC is produced to point D and angle BAC=60degree and angle ACD =1 10 degree, then the value of angle X is :

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Answered by naman3009
0
angle ACB = 180 - 110 = 70

Now, ACB = 70 BAC = 60 ABC = x
ACB+BAC +ABC = 180 (Angle Sum Property)
70 + 60 + x = 180
130 + x = 180
x = 180-130
x = 50
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