Question

in figure there are two concentric circles with o p r and P Q R S are tangents to the inner circle from point lying on the outer circle if p r is equal to 7.5 CM then PS is equals to​

Answer 1

$\huge \bold{hlo \: mate}$

Join OP. Now since, APQ is a tangent to the smaller circle so, OP = 90 degree.

Since, the length of tangents drawn from a common point to a circle is equal

So, AB = AP

Also, in the bigger circle, AQ is the chord and OP is the perpendicular to the chord.

Since, in a circle, a perpendicular drawn from the center of the circle to a chord bisects it.

Therefore, AP = PQ.

Hence, AQ = AP+PQ = 2*AP = 2* AB = 2*(7.5) = 15 cm