Question

in figure triangle ABC equals to triangle DCB equals to 90 degree then ab = 26 and BC = 28 then a triangle abc by a equals to​

Answer 1

Answer:

Given ∠B=90

∘

,AB=28cm,BC=21cm

Area of shaded region=ar△ABC+area of semicircle AC-ar quarter circle BC

=

2

1

×BC×AB+

2

1

×π(

2

AC

)

2

−

4

1

×π(BC)

2

=[

2

1

×21×28]+[

2

1

×

7

22

×

4

1

(

28

2

+21

2

)

2

]−

4

1

×

7

22

×21×21

=294+[

28

11

×1225]−346.5

=294+481.25−346.5=428.75㎠

Answer 2

in figure triangle ABC equals to triangle DCB equals to 90 degree then ab = 26 and BC = 28 then a triangle abc by a equals to

area of triangle=1/2xbxh

area of triangle = 1/2x26x28