In figure, ZABC = 69º and ZABC = 31°, find ZBDC.
(See Lesson-15)
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angle D is 80°. hope it's help please mark as brainlist
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Given :
- ∠ABC = 69°
- ∠ACB = 31°
To find :
- ∠BDC
According to the question,
➨ ∠ABC + ∠ACB + ∠BAC = 180°
Reason : Angle sum property
➨ 69° + 31° + ∠BAC = 180°
➨ 100° + ∠BAC = 180°
➨ ∠BAC = 180° - 100°
➨ ∠BAC = 80°
➨∠BAC = ∠BDC
Reason : Angle in the same segment
➨ ∠BDC = 80°
So,
- ∠BDC = 80°
_____________________
Theorem :
The angle subtended by an arc of a circle at the centre is doubled the angle made by the same arc at any point of the circumference.
Theorem :
Angle in a semicircle is right angle (90°).
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