Question

In first case a force of 5 N is apped on a object for 6 minutes and displaces it by 10 meters. In
second case. A force of 10 N is apped on the same object for 3 minutes and displaces it by 5 meters. In
which case there is more work done?
al first case
o Second case
ctn both cases, work done is same
on both cases, work oone is zero​

Answer 1

Workdone will be same.

Since ,W = F X S

1st case , W=50N

2nd case, W=50N

Answer 2

Answer:

Work done = Force × displacement

Since in both the cases force and displacement are same , work done will be same in both the cases I. E. work done = 5 × 10 = 50N