Question

In first excited state of hydrogen atom, radius is found to be 21.2 * 10A. .calculate it's Bohr radius in ground state. calculate total energy of atom in second excited state


pls solve it fast... ​

Answer 1

r (0)= 21.2 x 10^-11 m

First excited state means,

n = 2

r(0) = n^2  x  r(1)

r(1) = 21.2 x 10^-11 / 4

     = 5.3 x 10^-11 m  

E = - 13.6 / n^2

  = - 3.4 eV

Hope this may help you !