Question

In garden pea a dihybrid cross was made. In f2 9/16 members where showing same phenotype the phenotype was.

Answer 1

The phenotype of f2 generation will be Round Yellow.

Explanation:

The genotype of parents can be written as RRYY (round yellow) and rryy (green wrinkled). In the f1 generation the genotype will be RrYy which after undergoing selfing will produce RRYY: RRyy: rrYY: rryy in the ratio of 9:3:3:1

ie 9 will be Round Yellow.

Answer 2

If in F2 generation 9/16 members were showing the same phenotype, the phenotype was yellow and round seeds.

• In pea's dihybrid cross, the two characteristics studied were the shape and the color of the seeds.
• The round (R) shape and yellow (Y) color are dominant over wrinkled (r) and green (y) seeds.
• The phenotypic ratio obtained after F2 generation was:

    Yellow Round : Green Round : Yellow Wrinkled : Green wrinkled

    = 9   : 3    : 3    : 1

• This ratio also confirms that these two traits are sorted independently.