Question

in given circle <aob =60°,find <acb​

Answer 1

Step-by-step explanation:

Given O is the centre of circle.

∠AOB=60

o

To find : ∠ACB, ∠ADB

∠ACB=

2

1

∠AOB

(Angle subtended by the arcA at centre is twice the angle subtended by the arc on the circle)

∴ ∠ACB=30

o

ACBD is a cyclic quadrilateral

Opposite angles in a cyclic quadrilateral sum 180

o

∠ACBb+∠ADB=180

o

30

o

+∠ADB=180

o

∠ADB=150

o

∠ACB=30

o

∠ADB=150

o