In given figure, a circle is inscribed in a ΔABC, such that it touches the sides AB, BC and CA at points D, E and F respectively. If the lengths of sides AB, BC and CA are 12 cm, 8 cm and 10 cm respectively, find the lengths of AD, BE and CF
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Answer:
We know that AD= AF
BD=BE
CE=CF
Let AD= AF=x
BD=BE=y
CE=CF=z
Then x+y=12
y+z=8
x+z=10
On Solving above equation we get x=7,y=5,z=3
So AD=7 , BE=5 , CF= 3
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