in given figure AB=BD and CA=DC
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Answered by
8
Step-by-step explanation:
In ∆ BCA and BCD
AB = BD (given)
AC = CD ( given)
BC = BC ( common)
therefore ∆ BCA ~ ∆ BCD [ AAA]
angle ABC = angle CBD
Answered by
2
Step-by-step explanation:
In triangle BCA and BCD
AB=BC given
BC =BC given
Triangle BCA =BCD SSS
Angle ABC =Angle CBD. CPCT
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