In given figure, ABCD is a rectangle. The radius of the semicircles drawn on AD and Dy BC as diameters and radius of circle drawn in between is the same. If BC 7 cm find the area of the shaded region
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Step-by-step explanation:
We have,
a
x−1 =bcaa x
=abca x =abc
a=(abc)
1/x …(1)
Similarly,
b=(abc)
1/y …(2)c=(abc) 1/z …(3)
Multiply (1),(2),(3)
abc=(abc)
1/x .(abc) 1/y .(abc) 1/z
abc=(abc) 1/x+1/y+1/z
∴ x1 + y1 + z1
=1xyzxy+yz+zx =1xy+yz+zx=xyz
xy+yz+zx−xyz=0
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