Question

in given figure angle B=90,BD=6cm CD=9cm AD=10cm FIND PERIMETER OF TRIANGLE ABC

Answer 1

given ,
angle B=90°
BD=6cm
CD=9cm
AD=10cm
for the above information we can say that D is a point on AC
therefore AC=AD+CD=9cm+10cm=19cm
now,
we know that ,
the perimeter of a triangle=sum of all the sides
therefore ,
AB+BC+AC=AB+BC+19cm.....1
now,
since the triangle is a right anged triangle.
therefore, AC=AB+BC
=>AB+BC=19cm....2
1=AB+BC+19cm=19cm+19cm(from 2)
=38cm
hope its the required answer....