Question

in given figure, BC is a diameter of the circle and AD bisects angle BAC. find angle BCD.

Answer 1

angle BCD is 45°.
because angle ACD IS 90 angle in a semicircle is 90
bc bisect angle acd

Answer 2

∠BCD =  45° if in given figure, BC is a diameter of the circle and AD bisects angle BAC

Step-by-step explanation:

∠BCD = ∠BAD  ( angle formed by same chord BD in same arc segment)

∠BAC = 90°  ( as BC is Diameter )

AD bisects ∠BAC

=> ∠BAD = (1/2)∠BAC

=>  ∠BAD = (1/2)90°

=> ∠BAD = 45°

∠BCD = ∠BAD

=> ∠BCD =  45°

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