Question

In given figure bc is diameter . If ab =3cm ac = 4 cm and angle A= 90° find the shaded region region (Pi = 3.14)



Plz slove and send

Answer 1

In triangle ABC

${bc}^{2} = {3}^{2} + {4}^{2}$

${bc}^{2} = 25$

$bc = 5$

Area of triangle ABC

$\frac{1}{2} \times b \times h$

$\frac{1}{2} \times 3 \times 4$

$= 6c {m}^{2}$

Since BC is diameter

$radius = \frac{1}{2} bc$

Radius= 2.5cm

Area of circle =

$\pi {r}^{2}$

$3.14 \times 2.5 \times 2.5$

$= 19.625c {m}^{2}$

Area of shaded part= Area of circle- Area of triangle ABC

$19.625 - 6$

$= 13.625c {m}^{2}$