in given figure if QT is perpendicular to PR and angle PQR is equals to 40 degree and Angle SPR is equal to 30 degree find X,Y and supplementary angle of y
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6
by angle sum property of a triangle,
y=80°
supplementary of y is 100°
angle x=50°
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Answered by
7
in QTR, Angle T is 90 SO
90+40+X=180
X=50
NOW IN PSR 30+50+ANGLE PSR=180
PSR=100
SO Y=80
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