in given figure if TP and tq are two tangents to a circle with Centre O so that angle poq equal to 140 degree then find angle ptq
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there is no fig.
but I think the ans.is 70degree...as the angle subtends at the centre of a circle is double the angle subtends by 2 tangents at a particular point.
but I think the ans.is 70degree...as the angle subtends at the centre of a circle is double the angle subtends by 2 tangents at a particular point.
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23
Answer:
Step-by-step explanation:
<POQ=110°
<OPT=<TQO=90°(the tangent at any point of a circle is perpendicular to the radius through the point of contact)
<POQ+<OQT+<OPT+<PTQ=360°(sum of interior angles are 360°
110°+90°+90°+<PTQ=360°
290°+<PTQ=360°
360°-290°=<PTQ
70°=<PTQ
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