In given figure O is the centre of the circle angle CBE = 25 and angle DEA = 60, then find the measure of angle ADB.
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Given : O is the centre of the circle ∠CBE = 25° and ∠DEA = 60°,
To find : the measure of ∠ADB.
Solution:
∠CBE = ∠CBD as E lies on BD
∠CBD = ∠CAD Angle by same chord/arc CD in same arc segment
=> ∠CAD = 25°
∠EAD = ∠CAD as E lies on CA
=> ∠EAD = 25°
∠EAD + ∠ADE + ∠DEA= 180° Sum of angles of Triangle
=> 25° + ∠ADE + 60°= 180°
=> ∠ADE = 95°
∠ADB = ∠ADE
=> ∠ADB = 95°
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