In given figure. P is centre of circle . In which angle CAP is 70 degree and angle CDA is x . find the value of x.give the answer
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anglePAC+anglePCA+angleCPA=180°
【anglePAC=anglePCA because if opposite side are equal then opposite angle is also equal. 】
Now putting the value of angle PAC=70°
70°+70°+angleCPA=180°
angleCPA=180°-140°
angle CPA=40°
In ∆APD angle PAC is exterior angle so,
anglePDA+anglePAD=angleCPA
【anglePDA=anglePAD because if opposite side are equal then opposite angle is also equal. 】
anglePDA=x. (Given)
x+x=40°. (putting value of angleCPA)
2x=40
x=40/2
x=20°
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anglePAC+anglePCA+angleCPA=180°
【anglePAC=anglePCA because if opposite side are equal then opposite angle is also equal. 】
Now putting the value of angle PAC=70°
70°+70°+angleCPA=180°
angleCPA=180°-140°
angle CPA=40°
In ∆APD angle PAC is exterior angle so,
anglePDA+anglePAD=angleCPA
【anglePDA=anglePAD because if opposite side are equal then opposite angle is also equal. 】
anglePDA=x. (Given)
x+x=40°. (putting value of angleCPA)
2x=40
x=40/2
x=20°
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surender4777:
Thanx
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