the radii of the ends of the bucket 45cm higher are 28cm and 7 cm find the volume and the total surface area
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Step-by-step explanation:
The bucket is in the shape of the frustum of a cone.
Volume of a frustum of a cone = 1/3 × π × h × (r^2 + r.r' + r'^2
TSA of frustum of a cone = πl (r + r') + πr^2 + πr'^2
CSA of a frustum of a cone = πl (r + r')
Here, r and r' are radii of circular ends, h is the frustum's height and l is it's slant height where l = ✓[h^2 + (r - r')^2]
Substituting the given values,
Volume = 1/3 × 45 × 22/7 × (28 × 28 + 28 × 7 + 7 × 7 = 48510 cm^3
TSA = 22/7 × ✓[45 × 45 + (28 - 7)^2] (28 + 7) + 22/7 × 28 × 28 + 22/7 × 7 × 7 = 5462.47 + 2618 = 8080.47 cm^2
BrainyBeast:
but your tsa is wrong bcuz it should be 7 cm instead of 28 cm
as bucket will be open from broader end
Sorry my bad..
no problem
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