Question

in given figure ray AB || ray CD.Find measures of angle PCD and angle CPD

please answer step by step explanation soon thank you :)​

Answer 1

ABllCD

/PDC= /BAP=56° because it is alternative interior angle

AD is straight line

/APC +/2CPD=180

100+/CPD=180

/CPD= 80°

in triangle PDC

we know that sum of all angle = 180

/CPD+/PCD/PDC=180

80+/PCD+56=180

/PCD= 180-136= 44

hence the required angles are

/CPD= 80 and /PCD= 44

Answer 2

Answer:

Here, angle APC and angle CPD are on the same line addition of these two angles will be 180°.

APC + CPD = 180°

100 + CPD = 180°

CPD = 180 - 100°

CPD = 80°

Now, AB || CD

So, BAD = ADC = 56°

Measure of all angles of ∆ is 180°

angle P + C + D = 180°

80° + C + 56° = 180°

C = 180 - 136°

angle C = 44°

Angle PCD = 44°