The students of a Vidyalaya were asked to participate in a competition for making and
decorating penholders in the shape of a cylinder with a base, using cardboard. Each
penholder was to be of radius 3 cm and height 10.5 cm. The Vidyalaya was to supply
the competitors with cardboard. If there were 35 competitors, how much cardboard
was required to be bought for the competition?
Answers
Answered by
41
Given:
- Radius of penholder, r = 3 cm
- Height of penholder, h = 10.5 cm
To find:
- How much cardboard was required to be bought for the competition?
Solution:
We know that,
Penholder has shape of cylindrical shape.
Cardboard required by 1 competitor = CSA of one penholder +Area of base
⇏ 2πrh + πr²
⇏ 2 × 22/7 × 3 + 10.5 + 22/7 + (3)²
⇏ 198 + 198/7
⇏ 1584/7 cm²
★ Cardboard required for 35 competitors,
⇏ 35 × 1584/7
⇏ 7920 cm²
Hence, 7920 cm² of cardboard was required to be bought for the competition.
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More to know:
- Curved Surface Area of cylinder = 2πrh
- Total surface area of cylinder = 2πr(r + h)
- Volume of cylinder = πr²h
Answered by
1
Answer:
Answer
Given:
R=3cm, H=10.5cm
⇒Surface area = Curved Surface Area + Base Area
=2πrh+πr
2
=2×
7
22
×3×
10
10.5
+
7
22
×3×3cm
2
=198+
7
198
cm
2
=
7
1584
cm
2
⇒Area of cardboard sheet used by competitor =
7
1584
cm
2
⇒Area of cardboard sheet used by 35 competitors =
7
1584
×35
=7920cm
2
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