in given figure ray AZ bisects angle BAD and angle DCB :
a) prove that the∆BAC=~∆DAC
b) is AB = AD ?
c) is CD = CB
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Answer:
a.)
In ∆BAC AND ∆DAC
ANGLE DAC = ANGLE BAC(GIVEN)
ANGLE DCA = ANGLE BCA (Given)
AD IS A COMMON SIDE
SO, ∆BAC congruence ∆DAC (A.S.A)
b.)
Yes AB=AD (C.P.C.T.)
c.)
Yes CD=CB(C.P.C.T.)
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