In given figure,Ray OE bisects <AOB and OF is a ray opposite to OE. show that <FOB=<FOA
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1) Ray OE bisectsAOB and OF is a ray opposite to OE . Show that FOB = FOA
2)Lines AB , CD and EF intersect at O . find the measures of AOC , COF , DOE and BOF
Given that OE bisects angle AOB
∴, angle AOE=angle EOB
Let it be x,
angle AOE=angle EOB=x
Here OF and OE form a straight line.
So, angle is 180°.
angle FOA+angle AOE=180°
angle FOB+angle BOE=180°
∴, angle FOA+angle AOE=angle FOB+angle BOE
⇒angle FOA=angle FOB (∵angle AOE=angle BOE)
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