Question

In given figure, the measure of angle BCA is
plss explain as well and I will mark you as brainliest
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Answer 1

${\underline{\orange{\textsf{\textbf{Answer : }}}}}$

➡ $\angle C = 55°$

${\underline{\blue{\textsf{\textbf{Explantion : }}}}}$

Given that, In an isoceles ∆ two angles are there $\angle A = 2x + 20°$

$\angle B = 50°$

$\angle C = ?$

So here, we need to find the value of $\angle C$

As we know that,

❃ Sum of all angles in a ∆ is 180°

Therefore :

We can say that,

➡ $\angle A$ + $\angle B$ + $\angle C$ = 180°

According to the question :

$\sf \longrightarrow (2x + 20) \degree+ 50 \degree+ \angle \: C = 180 \degree$

$\sf \longrightarrow \: 2x \degree+ 70 \degree+ \angle \: C = 180 \degree$

$\sf \longrightarrow \: 2x \degree + \angle \: C =( 180 - 70 )\degree$

$\sf \longrightarrow \: 2x \degree + \angle \: C = 110 \degree$

$\sf \longrightarrow \: \angle \: C = \frac{110}{2}$

$\sf \green{ \longrightarrow \angle \: C = 55 \degree }$

Therefore

$\sf\angle C = 55°$

Answer 2

Answer:

➡ \begin{gathered}\angle C = 55° \\\end{gathered}

∠C=55°

{\underline{\blue{\textsf{\textbf{Explantion : }}}}}

Explantion :

Given that, In an isoceles ∆ two angles are there \angle A = 2x + 20°∠A=2x+20°

\angle B = 50°∠B=50°

\angle C = ?∠C=?

So here, we need to find the value of \angle C∠C

As we know that,

❃ Sum of all angles in a ∆ is 180°

Therefore :

We can say that,

➡ \angle A∠A + \angle B∠B + \angle C∠C = 180°

According to the question :

\begin{gathered}\sf \longrightarrow (2x + 20) \degree+ 50 \degree+ \angle \: C = 180 \degree\\\end{gathered}

⟶(2x+20)°+50°+∠C=180°

\begin{gathered}\sf \longrightarrow \: 2x \degree+ 70 \degree+ \angle \: C = 180 \degree\\\end{gathered}

⟶2x°+70°+∠C=180°

\begin{gathered}\sf \longrightarrow \: 2x \degree + \angle \: C =( 180 - 70 )\degree\\\end{gathered}

⟶2x°+∠C=(180−70)°

\begin{gathered}\sf \longrightarrow \: 2x \degree + \angle \: C = 110 \degree\\\end{gathered}

⟶2x°+∠C=110°

\begin{gathered}\sf \longrightarrow \: \angle \: C = \frac{110}{2} \\\end{gathered}

⟶∠C=

2

110

\begin{gathered}\sf \green{ \longrightarrow \angle \: C = 55 \degree } \\ \end{gathered}

⟶∠C=55°

Therefore

\begin{gathered}\sf\angle C = 55° \\\end{gathered}

∠C=55°