Question

in given figure , triangle ABC is an eqilateral triangle have each side equal to 10 cm and triangke PBC is a right angled triangle inside it the right angle at P in which PB = 8 cm. find area of shaded region

Answer 1

HEY DEAR MATE,

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HERE IS YOUR ANSWER


AREA OF THE EQUILATERAL TRIANGLE ABC
=√3÷4 a^2
=√3÷4 (10)^2. {100÷4=25}
=√3×25
=25√3

AREA OF THE RIGHT ANGLE TRIANGLE,
IN ∆PBC
(H)^2=P^2 + B^2
(10)2=(PC)^2+(PB)^2
100=(8)^2+ PC^2
100-64=PC^2
√36=PC
PC=6

AREA

=1÷2×PC×PB
=1÷2×8×6
=8×3
=24CM^2

NOW THE AREA OF SHADED PORTION

AREA OF ∆ABC-∆PBC

25√3-24

25×1.723 - 24
43.075-24
19.075

Answer 2

SORRY FOR BAD HANDWRITTING ...

HERE IS THE ANSWER