in given figure triangle ABC is right angled at C and ab^2 =2AC^2 prove that triangle ABC is an isosceles triangle
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Step-by-step explanation:
Given ABC is right-angled at C
and ab^2 =2ac^2 ------------------ 1
by Pythagoras theorem
we know
ab^2 = ac^2 + bc^2 ----------------- 2
from 1 and 2 equations
2ac^2 = ac^2 + bc^2
ac^2 = bc^2
ac = bc
therefore its an isosceles triangle as two sides are equal
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