Question

in //gm ABCD of the given figure the bisecto of angle c meets AD at e ce and ab extended to meet at f prove that bc =bf

Answer 1

according to figure ,
ABCD is parellelogram
hence AB||DC , AD|| CB
also angle DCB bisected by CE which meet in F
see triangle DEC and FEA
we know,
angle FEA=angle DEC
also ,
DC||AB||BF
hence ,
angle DCE=angle CFB
but angle DCE=angle FCB
hence,
angle CFB= angle FCB
so,
triangle BCF is isoceles triangle
hence ,
BC=BF

Answer 2

the attachment is the required answer