can anyone help me out question 5 and 6
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5)sin30=1/2 =60/length of the string
length of the string = 120 m
6)i)tan 45 =1=height of the tower 1.6m high from the ground/20
height of the tower =(20+1.6)m=21.6m
ii)tan 60 =(3^1/2)=height of the tower 1.6m high from the ground/20
height of the tower =(20.3^1/2 +1.6)m
.......
if it helped you please mark it as brainliest answer.Thank you .
length of the string = 120 m
6)i)tan 45 =1=height of the tower 1.6m high from the ground/20
height of the tower =(20+1.6)m=21.6m
ii)tan 60 =(3^1/2)=height of the tower 1.6m high from the ground/20
height of the tower =(20.3^1/2 +1.6)m
.......
if it helped you please mark it as brainliest answer.Thank you .
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