Question

In group of 58 people, 28 people drink tea only, 18 people drink coffe only and 10 people drink both coffe and tea then find number of people who drink neither of these?

Answer 1

2 people neither drink anything

Answer 2

This is a problem of union and intersection.
To solve this ,you just have to apply the formula
n(A union B) = n(A) +n(B) -n(A intersection B)
where,
A = who drinks tea only
B = who drinks coffee only
A union B = tea and coffee any one
A intersection B = Both of them
By putting the values, you will get 36,who drinks something.
Now, those who doesn't drink are (58-36)= 22 will be the answer.