In H C = CH - C = N, the no of carbon atoms
having sp, sp and sp
and sp. hybrid orbitals
respectively are
(A). 1, 2,0
(B) 1, 1,1
(C) 0, 1, 2
(D) 2, 1,0
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Answer:
your answer is option b us correct
Explanation:
1,11
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