Question

In his room, Dumpo has three trousers. One of them is black, the second is 1 point
blue, and the third is brown. In his room, he also has four shirts. One of
them is black and the other 3 are white. He opens his room in the dark and
picks out one shirt and one trouser pair without examining the colour. What
is the likelihood that neither the shirt nor the trouser is black?
O 1112
O 116
112
O 114​

Answer 1

Answer:

the answer is 1/2

Step-by-step explanation:

From question, Probability that trouser is not black = 2/3

Probability that shirt is not black = 3/4

Therefore, Required probability = 2/3×3/4=12

Answer 2

The probability that he will not take both is $\frac{1}{2}$

Given:

He has three trousers . One is black and second one is blue and the third is brown and in four shirts one is black, and three are white

To Find:

To get the probability that the shirt and the trouser he takes is not both blue and black

Solution:

Probability that trouser is not black = $\frac{2}{3}$

Probability that shirt is not black = $\frac{3}{4}$

Required probability = 2/3 x 3/4 = 1/2

Hence, the probability that he will not take both blue and black is 1/2

#SPJ2