Question

In horse racing competition there were 18 numbered 1 to 18.the organizers assigned a probability of winning the race to each horse based on horses health and training the probability that horse one would win is 1/7, that 2 would win is 1/8, and that 3 would win is 1/7.assuming that tie is imposible find the chance that one of these three will win the race

Answer 1

Probability of Horse 1, 2 and 3 winning is 1/7, 1/8, 1/7 respectively.

Probability of Horse 1, 2 and 3 not winning is (1-1/7), (1-1/8), (1-1/7)

i.e., 6/7, 7/8, 6/7 respectively.

There are three possible situations which will satisfy the given conditions:

a) Horse 1 win and horses 2 and 3 lose. Probability of this event happening = (1/7*7/8*6/7) = 3/28

b) Horse 2 win and horses 1 and 3 lose. Probability of this event happening = (6/7*1/8*6/7) = 9/98

c) Horse 3 win and horses 1 and 2 lose. Probability of this event happening = (6/7*7/8*1/7) = 3/28

Hence, the required probability is = (3/28 + 9/98 + 3/28) = 60/196  =15/49  ans

Answer 2

15/49 Is the correct one