Question

in households circuit, a fan of resistance 200 ohms, a bulb of 100 ohms and a TV of 100 ohm is connected to a main circuit of 220 V. what is the total resistance in the circuit and current through the main supply?​

Answer 1

Answer:

400Ω and 1.81A

Explanation:

200 om + 100 om + 100 om = 400 om

I= R/V

I = 11/20

i= 1.81 A

Answer 2

Answer:

The total resistance in the circuit is 40Ω, and the current through the main supply is 5.5 A.

Explanation:

In household circuits, the resistors are connected in parallel combinations.

The resistance of the fan is (R₁)=200Ω

The resistance of the bulb is (R₂)=100Ω

The resistance of the TV is (R₃)=100Ω

The total resistance is given as,

$\frac{1}{R_T}=\frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3}$             (1)

By putting the values in equation (1) we get;

$\frac{1}{R_T}=\frac{1}{200} +\frac{1}{100} +\frac{1}{100}$

$\frac{1}{R_T}=\frac{1+2+2}{200}=\frac{5}{200}$

$\frac{1}{R_T}=\frac{1}{40}$

$R_T=40\Omega$                (2)

The current through the main supply is given as,

$I=\frac{V}{R_T}$          (3)

By substituting the values in equation (3) we get;

$I=\frac{220}{40}=5.5A$           (∵V=220 given)

Hence, the total resistance in the circuit is 40Ω, and the current through the main supply is 5.5 A.