Question

In the ∆ABC, DE || BC. If AB : AD = 5 : 3 then area of ∆ABC : area of ∆ADE

is​

Answer 1

by Thales theorem AB/AD-1= DB/AB=2/5

SO AD= 2

DB=3

AS AREA OF SIMILAR TRIANGLES IS EQUAL TO THE SQUARE OF THE RATIO OF THEIR CORRESPONDING AREAS. SO RATIO WILL BE 25: 9

Answer 2

Answer:

Area of ∆ABC : Area of ∆ADE = 25:9.

Step-by-step explanation:

Given: ∆ABC & ∆ADE are similar triangles & AB : AD = 5 : 3.

To find the area of ∆ABC : area of ∆ADE.

We know that,  If two triangles are similar, then the ratio of any two corresponding segments (such as altitudes, medians, or angle bisectors) equals the ratio of any two corresponding sides.

So, area of ∆ABC : area of ∆ADE=(AB/AD)^2

                                                      =(5 : 3)^2

                                                      =25:9

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In the ∆ABC, ∆ABC & ∆ADE are similar triangles DE || BC. If AB : AD = 5 : 3 then area of ∆ABC : area of ∆ADE is: