In how many can the letters of the word PERMUTATIONS be arranged if the :
• there are always 4 letters between P and S ?
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[6.(9!/2!).2!]/(11!/2!)=6/55
6=(1,6).(2,7),(3,8),(4,9),(5,10),(6,11)th positions of p and s and p,s will arranged together in 2! ways,and for each ways remaining 9letters will arrange in (11!/2!) ways as t has twice,and the total sample points is (11!/2!)
6=(1,6).(2,7),(3,8),(4,9),(5,10),(6,11)th positions of p and s and p,s will arranged together in 2! ways,and for each ways remaining 9letters will arrange in (11!/2!) ways as t has twice,and the total sample points is (11!/2!)
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