In how many different ways can the letters of the word passenger be arranged such that the two s never occur together?
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Answer:
The answer to the given question is 70560
Step-by-step explanation:
The word PASSENGER has 9 letters. There are 2 'S's, 2 'E's which are repeating. Other letters are distinct
Total number of arrangements possible with these letters = 9! / ( 2! * 2! ) = 90720
Now,
We can count the arrangements in which all the 'S's are together.
For the same, group all the 2 'S's and consider it as a single packet.
So now there are 8 letters in which
2 'E's are there
Therefore,
Total number of such arrangements possible = 8! / 2!
= 20160
Therefore,
The number of ways in whichthe letters of the word passenger be arranged such that the two s never occur together =
90720 - 20160 = 70560
Hence,
The answer to the given question is 70560
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