In how many different ways can the letters of the word 'leading' be arranged in such a way that the vowels always come together? 360 480 720 5040
Answers
Answer:
So the given word is ' leading '.
We have to see the arrangements so that the vowels are together .
Number of letters in 'leading' is 7 .
Number of vowels in 'leading' is 3 .
Ways to create consecutive place
There are 5 ways of choosing a number so that there will be consecutive places .
Ways to create vowels
Now we will concentrate on the vowels .
There are 3 vowels that can be arranged in any way .
For the first choice there are 3 chances .
Then there are 2 chances .
Then there is 1 chance for the last remaining one .
So the vowels can be arranged in 3 × 2 × 1 = 6 ways .
Ways to create consonants
There are 4 consonants .
For the first consonant there will be 4 choices .
For the second ..... 3 choices and so on ...
Number of ways will be 4 × 3 × ... 1 = 24
Total ways
According to the Principle of counting :
Total number of choices will be = 24 × 6 × 5
⇒ 144 × 5
⇒ 720
So OPTION - 720 is correct .
Although everyone knows :
Ways to arrange n number of items = n! such that :
n! = 1 × 2 × .... n .
This is called factorial .
Question:
In how many different ways can the letters of the word 'leading' be arranged in such a way that the vowels always come together?
(a) 360
(b) 480
(c) 720
(c) 5040
Answer:
The correct answer is option (c) 720.
Step-by-step explanation:
The word 'leading' has 7 different letters.
When the vowels EAI are always together, they can be considered to form one letter.
Then, we have to consider the letters LNDG (EAI).
Now, letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be consider among themselves in 3! = 6 ways.
The required number of ways .
Therefore, the correct answer is option (c) 720.
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When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
 Required number of ways = (120 x 6) = 720.