Question

In how many months will rupess1020 amounts to 1037 at 5/2 simple intrest per annum

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Time=8\:months}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Principal(p) = 1020 \: rupees \\ \\ \tt: \implies Amount(A) = 1037 \: rupees \\ \\ \tt: \implies Rate\%(r) = \frac{5}{2} \% \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Time(t) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p + S.I \\ \\ \tt: \implies 1037 = 1020 + si \\ \\ \tt: \implies S.I= 1037 - 1020 \\ \\ \green{\tt: \implies S.I= 17 \: rupees} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies S.I = \frac{p \times r \times t}{100} \\ \\ \tt: \implies 17 = \frac{1020 \times 5 \times t}{2 \times 100} \\ \\ \tt: \implies \frac{17 \times 2 \times 100}{1020 \times 5} = t \\ \\ \tt: \implies t = \frac{3400}{5100} \times 12 \\ \\ \green{\tt: \implies t = 8 \: months}$

Answer 2

GIVEN :

☞Amount (A) = 1037 rupees

☞ Principle (P) = 1020 rupees

☞ Rate% (R%) = 5/2

To FIND:

☆Time (t)

Solution :

Amount = S.I + sum

1037 = S.I + 1020

1037 - 1020 = S.I

17 = S.I

So, we got S.I = 17 rupees.

Then,

$S.I = \frac{P \times R \times t}{100}$

$=>17 = \frac{1020 \times 5 \times t}{2 \times 100}$

$=>17 \times 200 = 5100 \times t$

$=>\frac{3400}{5100} = t$

$=> \frac{3400}{5100} \times 12 = t$

$=>8 \: months \: = t$