In how many way n books can be arranged so that two particular books are not together
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Books are arranged in shelf.
Final Answer : (n-1)! (n-2)
Steps:
1) Total no. of ways in which 'n' can be arranged in shelf = n!
2) Now, we will find out the number of ways in which 'n' books can be arranged in a shelf such that particular pair of books will always together .
Here,
We will consider two books as single book .
Total no. of books become = (n-1) .
The (n-1) books can be arranged in (n-1)! .
We considered two books together, which themselves can be arranged in 2! ways.
3) No. of ways in which particular books are together = (n-1)! x 2 ! .
4) Finally,
No. of ways in which 'n' books can be arranged in a shelf such that no two books are together = n! - (n-1)! x 2!
= n(n-1)! -(n-1)!x2
= (n-2) (n-1)!.
Final Answer : (n-1)! (n-2)
Steps:
1) Total no. of ways in which 'n' can be arranged in shelf = n!
2) Now, we will find out the number of ways in which 'n' books can be arranged in a shelf such that particular pair of books will always together .
Here,
We will consider two books as single book .
Total no. of books become = (n-1) .
The (n-1) books can be arranged in (n-1)! .
We considered two books together, which themselves can be arranged in 2! ways.
3) No. of ways in which particular books are together = (n-1)! x 2 ! .
4) Finally,
No. of ways in which 'n' books can be arranged in a shelf such that no two books are together = n! - (n-1)! x 2!
= n(n-1)! -(n-1)!x2
= (n-2) (n-1)!.
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