In how many ways 3 different resistance may be connexted together
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Consider resistors A, B, and C. A dash means series “-”, and double slash means parallel “//”.
A-B-C all series.
A//B//C all parallel.
A-B//C
A//B-C
A//C-B
(A-B)//C
(A-C)//B
A-(B//C)
I think I’ve gotten all possible combinations there. So eight combinations of three different resistors. This is with the assumption that all ends of each resistor must be connected to a node.
If not:
A-B
A//B
A-C
A//C
B-C
B//C
Another six combinations, where two resistors have each node connected, with the third resistor only having one lead connected and so it doesn’t matter where it is connected.
These are all combinations with only two outside connections. If you also include 3 phase configurations, then there are two more:
A, B, C in delta
A, B, C in star
Depending on how you count each connection, from two to twelve more connection configurations.
A-B-C all series.
A//B//C all parallel.
A-B//C
A//B-C
A//C-B
(A-B)//C
(A-C)//B
A-(B//C)
I think I’ve gotten all possible combinations there. So eight combinations of three different resistors. This is with the assumption that all ends of each resistor must be connected to a node.
If not:
A-B
A//B
A-C
A//C
B-C
B//C
Another six combinations, where two resistors have each node connected, with the third resistor only having one lead connected and so it doesn’t matter where it is connected.
These are all combinations with only two outside connections. If you also include 3 phase configurations, then there are two more:
A, B, C in delta
A, B, C in star
Depending on how you count each connection, from two to twelve more connection configurations.
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