plzz solve this sum
the chapter name is -pair of linear equation in two variables
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Let the age of Rajan be x,
Age of Jay be y.
x : y = 3 : 2
2x = 3y .
2x - 3y = 0 [ Equation 1 ]
After five years,
Age of rajan = x + 5
Age of Jay = y + 5 .
Given,
x+ 5 : y + 5 = 4 : 3
3x + 15 = 4y + 20
3x - 4y = 5 . [Equation 2 ]
Multiplying Equation ( 1 ) by 3 and Equation (2) by 2 .
6x - 9y = 0
6x - 8y = 10 ( Subtracting both equations)
==========
-y = -10
y = 10
Now, 2x - 3(10) = 0 , 2x = 30 , x = 15 .
Therefore ,Age of Rajan is 15 and Jay is 10 at present.
Age of Jay be y.
x : y = 3 : 2
2x = 3y .
2x - 3y = 0 [ Equation 1 ]
After five years,
Age of rajan = x + 5
Age of Jay = y + 5 .
Given,
x+ 5 : y + 5 = 4 : 3
3x + 15 = 4y + 20
3x - 4y = 5 . [Equation 2 ]
Multiplying Equation ( 1 ) by 3 and Equation (2) by 2 .
6x - 9y = 0
6x - 8y = 10 ( Subtracting both equations)
==========
-y = -10
y = 10
Now, 2x - 3(10) = 0 , 2x = 30 , x = 15 .
Therefore ,Age of Rajan is 15 and Jay is 10 at present.
Answered by
4
!!
Let x and y are the present ages of Rajan and Jay respectively.
A.T.Q.
x : y = 3 : 2
x / y = 3 / 2
2x = 3y
2x – 3y = 0 .....(1)
After five years,
Rajan's age = (x + 5) years
Jay's age = (y + 5) years
Now, A.T.Q.
x + 5 : y + 5 = 4 : 3
(x + 5) / (y + 5) = 4 / 3
3(x + 5) = 4(y + 5)
3x + 15 = 4y + 20
3x – 4y + 15 – 20 = 0
3x – 4y – 5 = 0 .....(2)
Multiplying (1) by 3 and (2) by 2 and then subtracting
6x – 9y = 0
6x – 8y = 10
_________
– y = – 10
y = 10
Substituting y = 10 in (1)
2x – 3 (10) = 0
2x – 30 = 0
2x = 30
x = 30 / 2
x = 15
Thus, present ages of Rajan and Jay are 15 and 10 years respectively.
____________________________________
Let x and y are the present ages of Rajan and Jay respectively.
A.T.Q.
x : y = 3 : 2
x / y = 3 / 2
2x = 3y
2x – 3y = 0 .....(1)
After five years,
Rajan's age = (x + 5) years
Jay's age = (y + 5) years
Now, A.T.Q.
x + 5 : y + 5 = 4 : 3
(x + 5) / (y + 5) = 4 / 3
3(x + 5) = 4(y + 5)
3x + 15 = 4y + 20
3x – 4y + 15 – 20 = 0
3x – 4y – 5 = 0 .....(2)
Multiplying (1) by 3 and (2) by 2 and then subtracting
6x – 9y = 0
6x – 8y = 10
_________
– y = – 10
y = 10
Substituting y = 10 in (1)
2x – 3 (10) = 0
2x – 30 = 0
2x = 30
x = 30 / 2
x = 15
Thus, present ages of Rajan and Jay are 15 and 10 years respectively.
____________________________________
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