Question

In how many ways 4 boys and 4 girls can be seated in a row so that boys and girls are
alternate ?​

Answer 1

Step-by-step explanation:

_ B _ B _ B _ B -> 4!*4!

_ G _ G _ G _ G -> 4!*4!

so, 2*4!*4! = 576*2 = 1152 answer)

Answer 2

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5 boys and 4 girls are to be seated in a row so that the girl gets the even places.

The 5 boys can be seated in 5! Ways.

For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).

B x B x B x B x B

So, the girls can be seated in 4! Ways.

Hence, the possible number of arrangements = 4! × 5! = 24 × 120 = 2880

Hope it's Helpful.....:)