Question

In how many ways 5 first prize 7 second prize and 9 third prize can be arranged in a single line on a table if all first prize trophies are kept together second prize trophies are kept together and all third prize are kept together

Answer 1

Answer:

Step-by-step explanation:

Total first prize(A) = 5;

Second prize(B) = 7 and third price(C) = 9;

We have to arrange them like ABC (All the same prizes together)

We can arrange ABC by 3! = 3*2*1 = 6 ways;

But in a A there 5 prize so arrange them by  5!

In the same way B = 7! and C = 9!

Total number of ways = 3!*5!*7!*9!