The radius of circle is 5cm and length of chord is 8cm. Find the distance of the chord from centre of the circle?
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Given:
The radius of circle is 5cm
Length of chord is 8cm
To find:
The distance of the chord from centre of the circle.
Solution:
Let , O be the centre of the circle.
AB is the chord = 8 cm
OB is the radius = 5 cm
OD is the distance between the centre and the chord.
OD is perpendicular to AB.
AB = AD + DB
AD = DB
AB = 2AD
AB = 8 cm
8 = 2AD
Therefore AD = 4cm
OD be the distance of the chord from centre of the circle.
We can calculate OD using Pythagoras theorem
OD² + AD² = OB²
OD² + 4² = 5²
OD² + 16 = 25
OD² = 25 - 16
OD² = 9
OD = √9
OD = 3cm
Final answer:
The distance of the chord from centre of the circle is 3cm
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